Question

the zeroes of polynomial 3x²-12x-5 are?​

Answer 1

Answer:

5 & -1

Step-by-step explanation:

use QD formula {b²-4(ac)}

3x²- 12x - 5 = 0

where a = 3 b = -12 c = - 5

(-12)²-4(3×-15) = 0

144+180= 0

324= 0

x= - b ±√b²-4(ac)÷ 2a

x = - (-12) + 18 ÷ 2×3 OR x = -(-12) - 18 ÷ 2× 3

x= 12+18÷6 OR. x= 12-18÷ 6

x= 30÷6. OR. x= -6÷6

x = 5. OR x= -1

therefore the roots are 5 & -1

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