The zeroes of polynomial is x² + 99x +127
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Answer:
I hope it is helpful.
Step-by-step explanation:
Let given quadratic polynomial be p(x) =x2 + 99x + 127.
On comparing p(x) with ax2 + bx + c, we get
a = 1, b = 99 and c = 127
Hence, both zeroes of the given quadratic polynomial p(x) are negative.
Alternate Method
the above condition.
So, both zeroes of the given quadratic polynomial are negative.
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