Question

=) The zeroes of polynomial x²+ 25x +156 are​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

${x}^{2} + 25x + 156 \\ {x }^{2} + 13x + 12x + 156 = 0 \\ \\ x(x + 13) + 12(x + 13) = 0 \\ \\ (x + 13) + (x + 12) = 0 \\ \\ hence x = - 13 - 12$

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