Question

the zeroes of polynomials x^2 -√x-12 are​

Answer 1

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Step-by-step explanation:

$x^{2} -\sqrt{x}-12\\x^{2} -4\sqrt{x}+3\sqrt{x}-12\\\\\sqrt{x}(x\sqrt{x}-4)+3(x\sqrt{x}-4)\\(x\sqrt{x}-4)(3+\sqrt{x})\\x=9 \\or \\x=4/\sqrt{x}$

Hence Founded

Answer 2

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered}x^{2} -\sqrt{x}-12\\x^{2} -4\sqrt{x}+3\sqrt{x}-12\\\\\sqrt{x}(x\sqrt{x}-4)+3(x\sqrt{x}-4)\\(x\sqrt{x}-4)(3+\sqrt{x})\\x=9 \\or \\x=4/\sqrt{x}\end{gathered}

x

2

−

x

−12

x

2

−4

x

+3

x

−12

x

(x

x

−4)+3(x

x

−4)

(x

x

−4)(3+

x

)

x=9

or

x=4/

x