Question

the zeroes of quadratic polynomial 3 x square - 48 are _________and _________​

Answer 1

Answer:

x=±4. Explanation: We begin by dividing both sides by 3 : 3 x23 =483. x2=16. Take the square root on both sides (and don't forget the ... plz make me brain list

Answer 2

Answer:

±4

Step-by-step explanation:

Given a quadratic polynomial such that,

3x^2 - 48

Now, to find the zereos.

We first need to make it a quadratic equation.

For that, we have to eauate this to 0.

Therefore, we will get,

=> 3x^2 - 48 = 0

Now, factorisation is needed to be done,

=> 3(x^2-16) = 0

=> x^2 - 16 = 0

=> x^2 - 4^2 = 0

=> (x+4)(x-4) = 0

Therefore, we have,

=> x = -4

And

=> x = +4

Hence, the zereos are ±4