Math, asked by praneshmurugesan29, 8 months ago

the zeroes of quadratic polynomial 3x²-48 are​

Answers

Answered by Rabza2511
30

Answer:

Answer is 4

Step-by-step explanation:

3x^2-48=0

3x^2=48

x^2=48/3

x^2=16

x=√16

x=4

Answered by aliyasubeer
0

Answer:

The zeroes of quadratic polynomial 3x²-48 are​ ONE POSITIVE AND ONE NEGATIVE.

Step-by-step explanation:

Given:

Let

  • AX²+BX+C=0
  • SUM OF THE VALUES=B/A
  • PRODUCT OF VALUES=C/A

3x^{2} -48=0\\3x^{2} =48\\X=+\sqrt{\frac{48}{3}} OR -\sqrt{\frac{48}{3}

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