Question

The zeroes of quadratic polynomial x^2-18x+81

Answer 1

Answer:

p(X)=x^2-18x+81

=x^2-9x-9x+18

=X(x-9)-9(x-9)

=(x-9)(x-9)

let p(X)=0

(X-9)(x-9)=0

x-9=0 , x-9=0

X=9. X=9

Answer 2

Answer:

9

Step-by-step explanation:

x²-18x+81=0

x²-9x-9x+81=0

x(x-9)-9(x-9)=0

x=9