Question

The zeroes of quadratic polynomial x2- 2x-8 ​

Answer 1

Answer:

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x-4)(x+2)=0

x=4,x=-2

zeros of quadratic polynomial is 4 and -2.

Answer 2

Answer:4,-2

Step-by-step explanation:

$x^{2} -4x+2x-8\\x(x-4)+2(x-4)\\(x-4)(x+2)$

Zeroes of polynomial: $4,-2$

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