Question

The zeroes of the given polynomia p(x)= x²+√2x+12​

Answer 1

given f(x)=x²+√2x+12

to find zeroes..

= x²+√2x+12=0

=x²+3√2x+2√2x+12=0

=x(x+3√2)+2√2(x+3√2)=0

=(x+2√2)(x+3✓2)

zeroes are 2√2 & 3√2

hope this helped u..

:)