the zeroes of the given polynomial f(x) = 2x ^ 3 + 3x ^ 2 - 11x - 6 .
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Let f(x) = x3 - 6x2 + 11x - 6 Given: (x-1)(x-2) are the zeros of f(x). product of zeros = (x-1)(x-2) = x2 - 2x - x + 2 = x2 -3x + 2 therefore, on dividing the f(x) with x2 - 3x + 2 , we get, x-3 Now, x - 3 = 0 x = 3 Hence, the other zero is 3.Read more on Sarthaks.com - https://www.sarthaks.com/401002/find-all-the-zeroes-of-the-polynomial-x-3-6x-2-11x-6-if-two-of-its-zeroes-are-1-and-2
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