The zeroes of the polynimial p(Y)=(4y+pi)(y-4pi) are
Answers
Answered by
1
Step-by-step explanation:
simple and crisp , very easy
Attachments:
Answered by
2
(4y+π)(y-4π)=0 has two solutions at 4y+π=0 or y-4π=0.
→ 4y+π=0 or y-4π=0
→ y=-π/4 or y=4π
Therefore, two zeros are -π/4, 4π
Similar questions