Question

the zeroes of the polynomial 2+x-x² are ​

Answer 1

$\huge\mathfrak\green{\underline{\underline{Solution}}}$

⠀

$\mathtt{ First \:, \:rearrange \:the \:polynomial}$

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$\mathtt{ -{x}^{2} \:+\: x\: + \:2}$

($\tt{ multiply \:by \:- }$)

$\mathtt{ {x}^{2} - x - 2}$

$\mathtt{ {x}^{2} - ( 2 - 1)x - 2}$

$\mathtt{ {x}^{2} - 2x + x - 2 }$

$\mathtt{ x ( x - 2) + 1( x - 2)}$

$\mathtt{( x - 2 )(x + 1)}$

$\mathtt{ taking ( x - 2) = 0}$

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${\boxed{\mathtt{ x = 2}}}$

$\mathtt{ taking ( x + 1) = 0}$

${\boxed{\mathtt{x = -1 }}}$

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$\mathtt{ hence,\: ( -1) \:and \:2 \:are \:the\:zeroes}$

$\mathtt{ of\: the\: polynomial}$