Question

The zeroes of the polynomial ... – 3.x – m (m + 3) are
(a) m, m + 3
(b) -m, m + 3 (c) m, -(m + 3)
(d) -m, -(m + 3)​

Answer 1

I'm guessing this is the full question

x^2-3x-m(m+3)

=x^2-3x-m^2-3m

Step-by-step explanation:

comparing the equation with ax^2+bx+c

a=1

b=-3

c=-m^2-3m

using the quadratic formula we get:

x= 3 +- √9-4(-m^2-3m)

-------------------------

2

factorising the values in the square root, we get

3+-√(2m+3)^2

---------------------

2

= 3+- (2m+3)

--------------------

2

x = m+3 or -m

therefore option b is the right answer

Answer 2

Answer:

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Step-by-step explanation:

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