Question

The zeroes of the polynomial (5y2 - 25) are -​

Answer 1

Required Answer:-

Given:

• 5y² - 25 = 0

To find:

• The roots of the given equation.

Solution:

We have,

➡ 5y² - 25 = 0

Adding 25 to both the sides, we get,

➡ 5y² - 25 + 25 = 0 + 25

➡ 5y² = 25

Dividing both sides by 5, we get,

➡ 5y²/5 = 25/5

➡ y² = 5

Taking square roots on both sides, we get,

➡ y = ±√5

Hence, the roots of the given quadratic equation are √5 and -√5.

Answer:

• The roots of the given quadratic equation are √5 and -√5

Answer 2

Required Answer:-

Given:

5y² - 25 = 0

To find:

The roots of the given equation.

Solution:

We have,

➡ 5y² - 25 = 0

Adding 25 to both the sides, we get,

➡ 5y² - 25 + 25 = 0 + 25

➡ 5y² = 25

Dividing both sides by 5, we get,

➡ 5y²/5 = 25/5

➡ y² = 5

Taking square roots on both sides, we get,

➡ y = ±√5

Hence, the roots of the given quadratic equation are √5 and -√5.

Answer:

The roots of the given quadratic equation are √5 and -√5