The zeroes of the polynomial 6x square + 17x - 88 are
(1) -2 ,9/2
(2) -8/3, 11/2.
(3) 2, -9 /2 . (4) -11/2 , 8/3
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Solution:
f(x)=6x^2+17x-88
We know that f(x)=0
=>6x^2+17x-88=0
=>6x^2-16+33x-88=0
=>2x(3x-8)+11(3x-8)=0
=>(2x+11)(3x-8)=0
=>2x+11=0 or 3x-8=0
=>x= -11/2 or 8/3
The option is (2).
Note:
If y is a zero of a polynomial,on substitution the answer would be zero.
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