Question

the zeroes of the polynomial f (x) =x^2-4x^2+5x-2​

Answer 1

$\bold{ANSWERS}$

Hey buddy

I think u have mistaken to type the question..

It should be

x^3-4x^2+5x-2=0

put 1, 0,-1 u will get satisfied with 1

Therefore 1 is zero

and rest solve quaratic u will get 2 more zeros

Answer 2

Hey mate here is your answer

x^2-4x^2+5x-2

-3x^2+5x-2

-3x^2+6x-1x-2

-3x(x-2) -1(x-2)

(x-2) (-3x-1)

If (x-2) = 0

then x=2

If (-3x-1)=0

then x=-1/3

x = 2 x = -1/3

Hope it helps you

Thank you