Question

The zeroes of the polynomial g(x) = x2 + 3x - 4 are
(2) -1,4
(1) 1,4
(3) -4,1
(4) -1-,4​

Answer 1

$x^{2} + 3x - 4 = 0$

$x ^{2} + (4 - 1)x - 4 = 0$

$x ^{2} + 4x - x - 4 = 0$

$x(x + 4) - 1(x + 4) = 0$

$(x - 1)(x + 4) = 0$

$either$

$x - 1 = 0$

$x = 1$

$or$

$x + 4 = 0$

$x = - 4$

3rd one is the correct answer

Answer 2

$\huge \mathfrak \pink{hello \: friend}$

g(x)= x²+3x-4=0

On splitting the middle term,

= x²+4x-x-4=0

= x(x+4)-1(x+4)=0

= (x-1)(x+4)=0

Now,

x-1=0

x= 1

x+4=0

x= -4

Thus, the zeroes are 1 and -4.

Answer: Option 3