Question

The zeroes of the polynomial p(x) = 3x^2 - 1 are
(a)1/3
(b)
$1 \div \sqrt{3}$

(c)
$- 1 \div \sqrt{3}$

(d)
$1 \div \sqrt{3} and - 1 \div \sqrt{3}$
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Answer 1

Answer:

go with opt. D

substituting these two value, you get will p(x) =0