Question

The zeroes of the polynomial P(x) x^2-3x are
a)0,0
B)0,3
C)0,-3
D)3,-3

Answer 1

B)0,3

because

0^0-3^0=0

3^2-3*3=0

Answer 2

Answer:

B) 0,3

Step-by-step explanation:

To find zero of this P(x) Equation

${x}^{2} - 3x = p(x)$

Take P(x)=0

${x}^{2} - 3x = 0 \\ \\ \therefore \: x(x - 3) = 0 \\ \\ \therefore \: x = 0 \: \: \: \: or \: \: \: \: (x - 3) = 0$

First zero x= 0

$x - 3 = 0 \\ \\ \therefore \: x = 3$

second zero x= 3

zeroes of P(x) = x²-3x Are 0 & 3