Question

the zeroes of the polynomial p(x)= x^2-x-(2+2k) is -4,then the value of k is

Answer 1

Answer:

Given polynomial : p(x) = x² - x - (2 + 2k)

It is given that - 4 is the zero of the above polynomial. It means that it can make the above polynomial equals to zero.

→ p(- 4) = (- 4)² - (- 4) - (2 + 2k) = 0

→ (16) - (- 4) - (2 + 2k) = 0

→ 16 + 4 - 2 - 2k = 0

→ 20 - 2 - 2k = 0

→ 18 - 2k = 0

→ 2k = 18

→ k = 18/2

→ k = 9

Hence, the value of k is 9.