Question

The zeroes of the polynomial p(x) = x(x - 1) (x - 2) are​

Answer 1

Answer:

p(x) = x(x-1)(x-2) = 0

or (x-1)(x-2)=0/x

or (x-1)(x-2)=0

now, either (x - 1) = 0   OR (x-2) = 0

thus either x = 1 OR x = 2

therefore the zeros of the polynomial are 1 and 2

Answer 2

$\bf{p(x) =x(x - 1)(x - 2) }$

Here,

$\underline{\underline{ \large \tt{x(x - 1)(x - 2) = 0}} }\\ \\ \dag \: \boxed{ \sf{x = 0}} \\ \\ \\ \circ \: \: \bf x - 1 = 0 \\ \dag \: \boxed{ \sf{x = 1}} \\ \\ \\ \circ \: \: \bf x - 2 = 0 \\ \dag \: \boxed{ \sf{x = 2}}$

Hence⤵

• Zeroes of p(x) are 0, 1, and 2