Math, asked by imoksha105, 3 months ago

The zeroes of the polynomial p(x)= x²-x-6​

Answers

Answered by sboy04811
0

Answer:

x²-x-6

x²-3x+2x-6

x(x-3)+2(x-3)

(x-3)(x+2)

Answered by mentorman2346
0

Answer:

alpha is 3 & beta is -2.

Step-by-step explanation:

GIVEN : P(X) = x^2 - x - 6 = 0.

TO FIND : ZEROES OF THE POLYNOMIAL.

(SUCH THAT FIND THE VALUE

OF ALPHA & BETA).

SO, LETS FIND IT,,

AS WE KNOW THAT,,

P(X) = x^2 - x - 6. = 0.

; x^2 - x - 6 = 0.

: x^2 - 3x + 2x - 6 = 0

: x(x-3) + 2(x-3) = 0.

: (x-3)(x+2) = 0.

either,

x-3 = 0. OR. x+2 = 0.

: x = 3. : x = -2.

THEREFORE, alpha = 3.

beta = -2.

HOPE IT WILL BE HELPFUL!!..

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