The zeroes of the polynomial p(x)= x²-x-6
Answers
Answered by
0
Answer:
x²-x-6
x²-3x+2x-6
x(x-3)+2(x-3)
(x-3)(x+2)
Answered by
0
Answer:
alpha is 3 & beta is -2.
Step-by-step explanation:
GIVEN : P(X) = x^2 - x - 6 = 0.
TO FIND : ZEROES OF THE POLYNOMIAL.
(SUCH THAT FIND THE VALUE
OF ALPHA & BETA).
SO, LETS FIND IT,,
AS WE KNOW THAT,,
P(X) = x^2 - x - 6. = 0.
; x^2 - x - 6 = 0.
: x^2 - 3x + 2x - 6 = 0
: x(x-3) + 2(x-3) = 0.
: (x-3)(x+2) = 0.
either,
x-3 = 0. OR. x+2 = 0.
: x = 3. : x = -2.
THEREFORE, alpha = 3.
beta = -2.
HOPE IT WILL BE HELPFUL!!..
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