the zeroes of the polynomial p(x)= x²-x-72are (a)9,-8 (b)-9,8 (c)-9,-8 (d)9,8
Answers
Answered by
4
Answer:
a is your answer.
Step-by-step explanation:
p(9) = 9^2 - 9 - 72
= 81 - 9 - 72 = 0
p(-8) = (-8)^2 - (-8) -72
= 64 + 8 - 72 = 0
Answered by
0
option a is correct
Step-by-step explanation:
if x=9
(9)²-(9)-72
81-9-72
=0
if x=8
(-8)²-(-8)-72
64+8-72
72-72
=0
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