Math, asked by rajvanshu069, 8 months ago

the zeroes of the polynomial p(x)= x²-x-72are (a)9,-8 (b)-9,8 (c)-9,-8 (d)9,8​

Answers

Answered by vinay13893
4

Answer:

a is your answer.

Step-by-step explanation:

p(9) = 9^2 - 9 - 72

= 81 - 9 - 72 = 0

p(-8) = (-8)^2 - (-8) -72

= 64 + 8 - 72 = 0

Answered by gkakran780
0

option a is correct

Step-by-step explanation:

if x=9

(9)²-(9)-72

81-9-72

=0

if x=8

(-8)²-(-8)-72

64+8-72

72-72

=0

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