Question

The zeroes of the polynomial
$x {}^{2} - 7x + 12$
are​

Answer 1

Answer:

HEY MATE

GOOD EVE ♥

X^2 - 7X + 12 = 0

X^2 - 4X - 3X + 12 = 0

X ( X - 4 ) -3 ( X - 4 ) = 0

( X - 4 ) ( X - 3 ) = 0

X = 3 , 4

HOPE IT HELPS !!!

Answer 2

Answer:

${x}^{2} - 7x + 12 \\ \\ {x}^{2} - 4x - 3x + 12 \\ \\ x(x - 4) - 3(x - 4) \\ \\( x - 3)(x - 4) \\ \\ take \: (x - 3) = 0 \: \: \: and \: \: (x - 4) = 0 \\ \\ x = 3 \: \: \: and \: \: \: x = 4 \\ \\ henc \: the \: value \: of\: x = 3 \: and \: 4$