Question

The zeroes of the polynomial x^2 +13x+40 are

Answer 1

Answer:

(x+5)(x+8)

Step-by-step explanation:

Answer 2

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$\bold {According \: to \: Question}$

$x^{2} +13x+40=0$

$x^{2} +5x+8x+40=0$

$x(x+5)+8(x+5)$=0

$(x+8)(x+5)=0$

$x=-8;x=-5$

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