Question

. The zeroes of the polynomial (x-2)²-4 are *

1 point

0, -2

0, 2

0, -4

0, 4

​

Answer 1

Answer:

hiiiiii

4 is the right answer

Answer 2

Answer:

0,4

Step-by-step explanation:

$(x - 2) {}^{2} - 4 = 0$

${(x - 2)}^{2} = 4$

$x - 2 = \sqrt[ \frac{ + }{ - } ]{4}$

$x - 2 = \frac{ + }{ - } 2$

$if \: x \: = 2$

$then \: \: x - 2 = 2 \\ x = 2 + 2 \\ x = 4$

$if \: \: x \: \: = - 2$

$then \: \: x - 2 = - 2 \\ x = - 2 + 2 \\ x = 0$