Math, asked by mohammedfayas007, 11 months ago

The zeroes of the polynomial x^2-3 are

Answers

Answered by Anonymous

4

Step-by-step explanation:

x²-3= 0

x²-(√3 )²= 0

(x+3) (x-3) = 0

x+3 =0 x-3=0

x=-3 x=3

Hope this answer will help you

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