Question

the zeroes of the polynomial (x²-3) are _______ and ______​

Answer 1

SOLUTION :

y = f ( x ) = x² - 3 = 0 [ GIVEN ]

${x}^{2} - \sqrt{3} = 0$

by a² - b² = ( a - b ) ( a + b )

$(x - \sqrt{3} )( x + \sqrt{3} ) = 0$

$x - \sqrt{3} = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: x + \sqrt{3} = 0$

$x = \sqrt{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - \sqrt{ 3}$

the zeroes of the polynomial( x² - 3 )is√3and-√ 3