Question

the zeroes of the polynomial x2-3 will be​

Answer 1

Step-by-step explanation:

Given:-

The polynomial is x^2-3

To find:-

Find the zeroes of the given Polynomial?

Solution:-

Given quardratic polynomial is x^2-3

Let P(x) = x^2-3

To get zeroes we write P (x) = 0

=> x^2-3 = 0

We know that 3 can be written as (√3)^2

=> x^2-(√3)^2 = 0

This is in the form of a^2-b^2

Where, a=x and b=√3

We know that

(a+b)(a-b)=a^2-b^2

=> (x+√3)(x-√3) = 0

=> x+√3 = 0 and x-√3 = 0

=>x = -√3 or √3

zeroes are √3 and -√3

Answer:-

The zeroes of the Polynomial are √3 and -√3

Used formulae:-

• (a+b)(a-b)=a^2-b^2

Additional information:-

• The Quadratic Polynomial has at most two zeroes since the degree is 2.

Answer 2

x²-3=0

x²=3

x=±root3

Therefore,the zeroes of the polynomial are

+root3 and -root3

Hope it helps!....