Question

the zeroes of the quadratic polynomial 2x²+x-10​

Answer 1

Answer:

2 or -5/2

Step-by-step explanation:

$2 {x}^{2} + x - 10 = 0 \\ \\ d = {1}^{2} - 4(2)( - 10) \\ \\ d = 1 + 80 \\ \\ d = 81 \\ \\ \sqrt{d} = 9 \\ \\ x = \frac{ - 1 + 9}{2 \times 2} \: \: \: \: \: or \: \: \: x = \frac{ - 1 - 9}{2 \times 2} \\ \\ x = 2 \: \: \: \: or \: \: \: \: x = \frac{ - 5}{2}$

Answer 2

Answer:

-5/2, 2

Step-by-step explanation:

2x^+x-10

= 2x^2-4x+5x-10

= 2x(x-2) + 5(x-2)

= (2x+5)(x-2)

now zeros r the solutions of the polynomials.

so of quadratic, there r 2 solutions.

2x+5= 0

x= -5/2 (I)

x-2=0

x= 2 (ii)

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