Question

The zeroes of the quadratic polynomial 4x2 + 15x + 9 are​

Answer 1

see the attached sheet ..

Answer 2

Answer:

The zeros of the polynomial $4x^{2} +15x+9=0$  are  

$x=\frac{-3}{4}\ and\ x=-3$

Step-by-step explanation:

It can be found out by using the quadratic formula,

$x=\frac{-b}{2a}$±$\frac{\sqrt{b^{2-4ac} } }{2a}$

In the polynomial $4x^{2} +15x+9$,  

$a=4,b=15,c=9$

substituting in the formula,

$x=\frac{-15}{2(4)}$±$\frac{\sqrt{15^{2}-4(4)(9) } }{2(4)}$

  $=\frac{-15}{8}$±$\frac{\sqrt{225-144} }{8}$

  $=\frac{-15}{8}$±$\frac{9}{8}$

implies either $x=\frac{-15+9}{8}$    or    $x=\frac{-15-9}{8}$

                          $=\frac{-3}{4}$            or       $=-3$

hence the answer.

thank you