Question

The zeroes of the quadratic polynomial a(x^2+1)-x(a^2+1) are​

Answer 1

Answer:

(viii) g(x) = a(x2+1)–x(a2+1) Hence, the zeros of the quadratic equation are a and 1/a. Hence the relationship between zeros and their coefficients are verified.

Step-by-step explanation:

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Answer 2

Answer:

We have been given,

a(x2 + 1) - x(a2 + 1) = 0

ax2 - (a2 + 1)x + a = 0

ax2 - a2x - x + a = 0

ax(x - a) - 1(x - a) = 0

(ax - 1)(x - a) = 0

Therefore,

ax - 1 = 0

ax = 1

x = 1/a

or,

x - a = 0

x = a

Hence, x = 1/a or x = a

Step-by-step explanation:

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