The zeroes of the quadratic polynomial are √2 and -√2, then the quadratic polynomial is ?
hardikmishra200:
the answer is. sum of zeroes=√2-√2=0. ; product of zeroes=√2×-√2=-2;. so the equation is. x^2-2=0
Answers
Answered by
13
Zeroes are root2, - root2
Sum of zeroes = root2 - root2 = 0
Product of zeroes = root2 × (-root2) = - 2
Required polynomial = x^2 - (sum of zeroes)x + Product of zeroes
= x^2 - (0)x + (-2)
= x^2 - 2
Sum of zeroes = root2 - root2 = 0
Product of zeroes = root2 × (-root2) = - 2
Required polynomial = x^2 - (sum of zeroes)x + Product of zeroes
= x^2 - (0)x + (-2)
= x^2 - 2
Answered by
11
Hola bro!!!!
Formula for making quadratic polynomial is ....



So your answer is ....

Hope it helps
Formula for making quadratic polynomial is ....
So your answer is ....
Hope it helps
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