The zeroes of the quadratic polynomial f (x)= x² + 7x + 12
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Answered by
3
Answer:
hi
your answer is here !
Step-by-step explanation:
Hai friend,
here is your answer,
The polynomial is x²+7x+12
a=1,b=7,c=12
Factors of x²+7x+12
=x²+4x+3x+12
=x(x+4)+3(x+4)
=(x+4)(x+3)
Zeroes of the polynomial
x²+7x+12 =0
(x+4)(x+3)=0
x= -4,-3
ZEROES = -4, -3
SUM OF ROOTS = -4-3=-b/a=-7/1
=> -7=-7
PRODUCT OF ROOTS= -4*-3=c/a
=> 12=12
hope helped
Answered by
1
Hey mate hope it helps you...
x² + 7x + 12 = 0
x² + 4x + 3x + 12 = 0
x(x+4) + 3(x + 4) = 0
(x+4)(x+3) = 0
x = -3 or -4
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