Question

The zeroes of the quadratic polynomial x^2 + 7x + 10 are
1 point

Answer 1

Answer:

- 5 & - 2

Step-by-step explanation:

= > x² + 7x + 10

Split the middle term in such a way so that the product of those parts will be equal to the product of first and last term:

Here, 7 = 5 + 2 , as 5 * 2 = 10

= > x² + (5 + 2)x + 10

= > x² + 5x + 2x + 10

= > x(x + 5) + 2(x + 5)

= > (x + 5)(x + 2)

Hence,

Zeroes of this polynomial are - 5 & - 2.

Answer 2

Answer:

-5,-2

Step-by-step explanation:

x^2+7x+10=0

x^2+5x+2x+10=0

x(x+5)+2(x+5)=0

(x+5)(x+2)=0

x=-2,-5