Question

The zeroes of the quadratic polynomial x^2+99x+127 are?​

Answer 1

Answer:

Hence we got both the zeroes as negative, i.e. x = -1.3, -97.7. Thus the given quadratic polynomial, \[{{x}^{2}}+99x+127\] has both zeroes negative

Answer 2

Answer:

x² + 99x + 127

it will not be divisible

both the zeroes will be positive

hope it helps