Question

the zeroes of the quadratic polynomial x^2 + kx + k k is not equal to 0 can not both be................

Q 12​

Answer 1

Answer:

0

Step-by-step explanation:

ZEROES OF $x^2+kx+k$ : $x=\frac{-k\pm\sqrt{k^2-4k} }{2}$.

Substitute k=0.

$x=\frac{0}{2} =0$

∴can not both be 0.

Answer 2

Concept

A polynomial equation whose highest degree term is 2 is called a quadratic polynomial equation. The general equation of a quadratic polynomial equation is given by $ax^{2} +bx+c=0$ , here a is always positive integer.

Given

The Quadratic polynomial equation x$x^{2} +kx+k= 0$ where k≠ 0.

Find

Relation between the zeroes.

Solution

we know a is always greater than zero i.e. it is a positive integer.

when a>0,b>0 and c>0 then all roots are negative.

when a>0,b>0c>0 then roots are of opposite sign.

when a>0,b<0,c>0 then both zeroes are positive

since b and c in x^2+kX+k=0 are positive then zeros have opposite sign, therefore both zeroes cannot be positive

Both the zeros cannot be positive.

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