Question

the zeroes of the quadratic polynomial x²-18+81are​

Answer 1

Answer:

${x}^{2} - 9x - 9x + 9 \times 9$

$x(x - 9) - 9(x - 9)$

$(x - 9)(x - 9) = 0$

$x = 9 \: is \: the \: answer$

Answer 2

Answer:

9 and 9

Step-by-step explanation:

x² - 18x + 81 = 0

x² - 9x - 9x + 81 = 0

x(x - 9) - 9(x - 9) = 0

(x - 9)(x - 9) = 0

(x - 9)² = 0

x = 9

The zeroes of the polynomial are 9,9.