Question

The zeroes of the quadratic
polynomial x2 - 18x + 81 are

Answer 1

Step-by-step explanation:

please like and follow.

Answer 2

$\bf{\underline{\orange{QUESTION:-}}}$

The zeroes of the quadratic

polynomial x2 - 18x + 81 are

$\bf{\underline{\orange{SOLUTION:-}}}$

• $\sf x^2 - 18x+81$

$\bf{\underline{\fbox{\orange{BY\: SPLITTING\: METHOD:-}}}}$

$\sf → x^2-18x+81$

$\sf→ x^2 -(9+9)x+81$

$\sf→ x^2-9x-9x+81$

$\sf→ x(x-9)-9(x-9)$

$\sf→ (x-9)(x-9)$

$\bf{\underline{\orange{HENCE:-}}}$

• The zeroes of the given polynomial are x - 9 or x = 9