Question

The zeroes of the quadratic polynomial x2 _18x +81 are

Both negative
One positive and one negative
Both positive and unequal
Both equal and positive​

Answer 1

Answer:

x2-18x+81=0

X2-9x-9x+81=0

x(x-9)-9(x-9)=0

(x-9)(x-9)=0

Thus, x has equal roots 9 and 9.

Thus option d is right