Question

The zeroes of the quadratic polynomial x²+99x+ 127 are
(a) both positive
(b) both negative
(c) one positive and one negative
(d) both equal

Answer 1

$\huge\bold{\displaystyle\rm\red{Answer}}$

The zeroes of the quadratic polynomial ${x}^{2} + 99x + 127 \:$ are :

$f(x) = {x}^{2} + 99x + 127$

● Comparing the given polynomial with

$a {x}^{2} + bx + c \: ,we \: get \: \\ a = 1 \: , \: b = 99 \: , \: c = 127 \\ \alpha + \beta = \frac{ - b}{a} = - 99 \\ \\ \alpha \beta = \frac{c}{a} = 127$

● Now , the product is positive and the sum is negative so both of the numbers must be negative.

So, both zeroes are negative.

Thus, (b) is the correct option.

Answer 2

Option b is correct.

b) both are positive