Question

The zeroes of the quadratic polynomial x² + 99x + 127 are:
both positive
both negative
one positive and one negative
both equal​

Answer 1

Answer:

Put p(x) =0

P(x)=x^2+99x+127

P(0)=0^2+99×0+127

=0+0+127

=127

Put p(x) =1

P(1)=1^2+99×1+127

=1+99+127

=227

put p(x) =-1

P(-1)=-1^2+99×-1+127

=1-99+127

=29

Step-by-step explanation:

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