Question

the zeroes of the quadratic polynomial x2+kx+k,kis not equal to 0
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Answer 1

Step-by-step explanation:

The zeroes of this polynomial cannot be positive.

Let us try solving the quadratic by giving values to k.

If we take k as 5 and solve, we will get x as -1.38 and -3.61.

On the other hand, if we take k as 4, then we will get x as -2.

If k is taken to be negative such as -3, then the roots will be both positive and negative.

Answer 2

Answer:

let f(x) = x²+kx+k

put, x²+kx+k=0

    x² = -kx - k

    x = √(-kx - k )

√(-kx-k) is a zero of the polynomial f(x)