Question

The zeroes of the quadratic polynomial y2 +43y+222 are​

Answer 1

Answer:

Answers

Step-by-step explanation:

Mitpoint braking

Answer 2

Answer:

$\frac{2}{3} \: \: \: \frac{ - 1}{7}$

ia the answer broooooooooo

Step-by-step explanation:

Given quadratic polynomial is 7y

2

−

3

11

y−

3

2

.

=

3

1

(21y

2

−11y−2)

=

3

1

(21y

2

−14y+3y−2)

=

3

1

[7y(3y−2)+(3y−2)]

=

3

1

(3y−2)(7y+1)

y=

3

2

, y=−

7

1

The zeroes of the polynomials are,

3

2

, −

7

1

Relationship between the zeroes and the coefficients of the polynomials-

Sum of the zeros=-

coefficient of y

2

coefficient of y

=−

⎝

⎜

⎜

⎜

⎛

7

−

3

11

⎠

⎟

⎟

⎟

⎞

=

21

11

Also sum of zeroes=

3

2

+(−

7

1

)

=

21

14−3

=

21

11

Product of the zeroes =

coefficient of y

2

constant term

=

7

−

3

2

=

21

−2

Also the product of the zeroes=

3

2

×(−

7

1

)=

21

−2

Hence verified.