The zeroes of tie quadratic polynomialx² + 35x+124 are
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D= b²-4ac= 35 ²- 4×1× 124 = 1225- 496 =729
x=-b+-√D / 2a = -35+- √729 / 2 = -35 +- 27 /2
x= -35 +27/2 = -8/2= -4
x= -35 -27/2 = -62 / 2 = -31
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