Math, asked by mariamerlines, 6 months ago

The zeroes of tie quadratic polynomialx² + 35x+124 are ​

Answers

Answered by anurag2147
1

D= b²-4ac= 35 ²- 4×1× 124 = 1225- 496 =729

x=-b+-√D / 2a = -35+- √729 / 2 = -35 +- 27 /2

x= -35 +27/2 = -8/2= -4

x= -35 -27/2 = -62 / 2 = -31

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