Question

the zeroes of x^2 -x-12are​

Answer 1

Step-by-step explanation:

x^2-x-12

x^2-4x+3x-12. (3×4=12)

x(x-4)+3(x-4)

(x+3)(x-4)

x+3=0. x-4=0

x= -3. x=4

the zeroes are -3 and 4