Question

the zeroes of x-2x-8:

( a ) (2,-4)

( b ) (4,-2)

(c ) (-2,-2)

( d) (-4,-4)​

Answer 1

Answer:

$x ^{2} - 2x - 8 \\ \\ = {x}^{2} - (4 - 2)x - 8 \\ \\ = {x}^{2} - 4x + 2x - 8 \\ \\ = x(x - 4) + 2(x - 4) \\ \\ = (x + 2)(x - 4) \\ \\ either \: x + 2 = 0 \\ \\ = > x = - 2 \\ \\ or \: x - 4 = 0 \\ \\ = > x = 4$

๛ So zeroes would be ( 4 , - 2 )

☞ option ( c ) ✔

# keep smiling ☺

Answer 2

Step-by-step explanation:

option C is the correct answer hope you get it.no explanation of this