Question

*
The zeroes of x2–2x -8 are:
1 point
O
(a)(2,-4)
O
(b)(4,-2)
0 (
(c)(-2,-2)
O (d)(-4,-4​

Answer 1

Answer:

(b) (4,-2)

Step-by-step explanation:

${x}^{2} - 2x - 8 = 0 \\ {x}^{2} - 4x + 2x - 8 = 0 \\ x(x - 4) + 2(x - 4) = 0 \\ (x - 4)(x + 2) = 0 \\ x = 4 \: and \: - 2$

Answer 2

Answer:

(b)(4,-2)

Step-by-step explanation:

x²-2x-8=0

==> (x-4)(x+2)=0

==>x=4,-2