Question

The zeroes of x2–2x–8 are:
*
O 2
(a)(2,-4)
O (b)(4,-2)
O (C)(-2,-2)
O (d)(-4,-4)​

Answer 1

Answer:

(4,-2)   option (b)

Step to Step explanation:

We have

f(x) = x2-2x -8

Now, put f(x) = 0

x2-2x -8 = 0

x2- 4x + 2x -8 = 0

x(x - 4) + 2(x - 4) = 0

(x - 4) (x + 2) = 0

x - 4 = 0 or x + 2 = 0

x = 4 or x = -2

So, the zeros of given polynomial are 4 and -2.