Question

The zeroes of x²–2x –8 is: 1.(2,-4) 2.(4,-2) 3.(-2,-2) 4.(-4,-4)

Answer 1

Answer:

1 let the value of x sq.=2 and x be -4

2sq. -2*-4-8

4+8-8=2

2 let the value of x sq.=4 and x be -2

4sq -2*-2-8=12

3 let the value of x sq.=-2 and x be -2

-2sq.-2*-2-8=0

4 let the value of x sq.=-4 and x be -4

-4sq.-2*-4-8=16

therefore 3 (-2,-2) is the zeroes of polynomial

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Answer 2

Answer:

$\Large{\underline{\underline{\bf{Option\:2:\:(4,-2)}}}}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• p(x) = x² - 2x - 8

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Zeros of the polynomial

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ x² - 2x - 8 = 0

→ By splitting the middle term method,

  x² - 4x + 2x - 8 = 0

→ Taking the common factors out,

   x (x - 4) + 2 (x - 4) = 0

   (x - 4) (x + 2) = 0

→ Either

  x - 4 = 0

  x = 4

→ Or

  x + 2 = 0

  x =  -2

→ Hence the zeros are 4 and -2

$\boxed{\bold{Zeros\:are\:4\:and\:-2}}$

→ Therefore option 2 is correct.

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The zeros of a polynomial can be found out by

• Using factor theorem

$x=\dfrac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

• Splitting the middle term
• Completing the square method